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We look at the differences between each term
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6 10 14 18
\ _/\_ /\_ /
4 4 4 |
The difference is four |
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The general formula for the nth term is:
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where a= the first term=6
n = the number of the term
D= the difference = 4 |
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| For this sequence |
nth term = 6 +(n-1)4
= 6 + 4n -4
= 2 + 4n |
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| We can now use this formula to work out the value of any term in the sequence. |
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| b) |
20th term =
2 + 4x20
= 82 |
because n=20 |
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| c) |
nth term = 42 |
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42 = 2 + 4n
40 = 4n
n=10 |
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So the 10th term is 42.
This formula will work for any linear sequence. In a linear sequence the difference is constant. 4 in the sequence above.
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| Quadratic Sequences |
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In this type the first difference is not constant. The second difference gives a constant.
For example: |
| 3,8,15,24,36……… is a sequence. |
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3 8 15 24 35
\_/\_ /\_ /\_ /
5 7 9 11
\_ /\_ /\_ /
2 2 2 |
1st difference
2nd difference |
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This is a quadratic sequence as the 2nd difference is a constant (in this case, 2.)
The general formula for a quadratic is:
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| nth term = a + (n-1)d1 + ½(n-1)(n-2)d2 |
| Where a = 1st term |
d1= 1st difference
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d2= 2nd difference
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| = 3 |
=5 |
= 2 |
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nth term = 3 + (n-1)5 + ½ (n-1)(n-2)2
=3 + 5n - 5 +n2 -3n + 2
=n2 +2n |
We can use this to find the 100th term:
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100th term = 1002 +200
= 10200 |
Provided that the second difference is a constant we can use this method for any quadratic sequence. |