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Algebra (Intermediate) - Factorising
 

Method 1 | Method 2 | Method 3 | Double Brackets
 

In algebra, we factorise by putting brackets into the expression.

There are three methods of factorising. 

Method 1: Common Factor

Example 1 : Factorise 3y + 6

In this case, 3 is a common factor because it will divide into 3y and 6

Therefore the answer is written as

  3(y + 2)

In the next example there are two common factors.

Example 2: Factorise 5y2 - 10y

5 and y are factors, so the answer is

  5y (y - 2)

When asked to factorise, we must take out all the common factors.
 

Method 2: Factorising Quadratic Expressions Containing Three Terms

A quadratic expression contains a squared term as its highest power.

Example 1: Factorise y2 + 5y + 6

In this method we use two brackets. Inside these we put the factors of the first and last terms as follows:

 
   y2
+
 5y        +  6
           
  (y y)       (6 1)
(3 2)

           Factors of the
              first term  

               Factors of the last term

Note: there are two pairs of factors of the last term in this case. We choose the pair which add up to the middle term (in this case, 5).

So the answer is (y +3 )(y + 2)

The signs of the terms can be different, as in the following case.

Example 2: Factorise

 y2 + 3y - 10

   
 
 
 

(y y)       (-5, 2)

                 (5, -2)
                 (-10, 1)
                 (10, -1)

In this case, only 5 + -2 = 3 (which is the middle term)

Answer = (y +5 )( y -2)

Example 3: Factorise  x2 - 7x + 12
 
(x x)      (- 3 - 4)
             - 3 + - 4 = - 7 (which is the middle term)

Answer: (x - 3 )(x - 4)

 

Method 3: Difference Between Two Squares

This method is for expressions containing two squared terms and the sign between them must be minus.

Example 1: Factorise x2  - 9

Both x squared and 9 are squared terms and a minus is between them so we can factorise in this way.

  x2
-
    9  
(x x)
   (3 3)  
      (x + 3)  (x - 3)  

Example 2: Factorise  y2 - 25
  (y y) (5 5)
  (y + 5)(y - 5)
Note: there is a + sign is in one bracket and a - sign in the other.
 
Combinations of these methods can be used on some expressions.

Example 3: Factorise 2y2 - 8

Common factor

 2(y2 - 4)
Difference between two squares

 2(y + 2)(y - 2)

Note: we can check any answer by removing the brackets. This is called 'expanding brackets'.

For example, 3(y + 2) = 3 x y + 3 x 2 = 3y + 6

Note: we multiply everything inside the bracket by 3.

5y(y - 2) = 5y x y + 5y x - 2 = 5y2 - 10y

 

Double Brackets

Example 1:
 
(y + 3)(y + 2) = y(y + 2) + 3(y + 2)

= y2 + 2y + 3y + 6

= y2 + 5y +6

Note: we multiply the second bracket by y and then by 3.

Example 2:
 
(y + 5)(y - 2) = y(y - 2) + 5(y - 2)

= y2 - 2y + 5y - 10

= y2 + 3y - 10



Example 3:
 
(x - 3)(x - 4) = x(x - 4) - 3(x - 4)

= xx - 4x - 3x + 12

= x2 - 7x + 12

 
Note: this time we multiply by -3. This changes the signs in the second bracket.